Question

Please help me solve From a previous question, the index of refraction of the liquid is 1.37

Answer 1

ANSWER

EXPLANATION

From the previous part, we have that the index of refraction of the liquid is 1.37, so we have to replace this in the equation and solve,

$\sin\theta_c=\frac{n_{air}}{n_{liquid}}=\frac{1.00}{1.37}\approx0.73$

And then, take the inverse of the sine to find the critical angle,

$\theta_c=\sin^{-1}0.73\approx46.9\degree$

Hence, the critical angle is 46.9°, rounded to the nearest tenth.