Evaluate those values into the expression:
[tex]\begin{gathered} 3c-b \\ so\colon \\ 3(-\frac{2}{15})-\frac{3}{10} \\ -\frac{6}{15}-\frac{3}{10}=\frac{-60-45}{150}=-\frac{105}{150}=-\frac{7}{10} \\ \end{gathered}[/tex]Answer:
[tex]-\frac{7}{10}[/tex]