Question

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 10 people took the trip. She was able to purchase coach tickets for $200 and first-class seats for $940 Sheyee her total budget for airfare for the trip, which was $4220. How many first-class tickets did she buy? How many coach tickets did she buy? number of first-class tickets bought = number of coach tickets bought =

Answer 1

Answer:

• The number of first-class tickets bought = 3

,

• The number of coach tickets bought =7

Explanation:

Let the number of first-class tickets bought = x

Let the number of coach tickets bought = y

A total of 10 people took the trip:

$\implies x+y=10$

Her total budget for the trip's airfare = $4220.

$\implies200y+940x=4220$

Next, solve the two equations simultaneously:

$\begin{gathered} x+y=10\implies x=10-y \\ 940x+200y=4220 \end{gathered}$

Substitute x into the second equation:

$\begin{gathered} 940(10-y)+200y=4220 \\ 9400-940y+200y=4220 \\ 9400-740y=4220 \\ 9400-4220=740y \\ 5180=740y \\ \frac{5180}{740}=y \\ y=7 \end{gathered}$

Recall: x=10-y

$\begin{gathered} x=10-7 \\ x=3 \end{gathered}$

Thus:

• The number of first-class tickets bought, x = 3

,

• The number of coach tickets bought, y =7