Question

Find the values of x and y in the equation below.a³b4a²b= a*b²X=

Answer 1

$(\frac{a^3b^4}{a^2b})^6$

To divide, subtract exponents to same base variables.

$(ab^3)^6$

Multiply exponents of exponents

$a^6b^{18}$

x= 6

y= 18