What is the area of parallelogram ABCD?This is a diagram of parallelogram ABCD. Point A is located at (2,1). Point B is located at (8,1). Point C is located at (11,5). Point D is located at (5,5).A. 30 units²B. 55 units²C. 24 units²D. 12 units²

Respuesta :

If we draw the given points, we have the following:

The area of a parallelogram can be calculated as the height of it multiplied by its lenght of the base.

In this case, the height will be the distance of the coodinate y = 1 to the coordinate y = 5, which is equal to Δy = 5-1 = 4.

And the base is the distance from the point A to point B, which can be calculated as Δx = 8 - 2 = 6

Now, using the formula, we have:

[tex]\begin{gathered} A_{parallelogram}=b\times h \\ \\ A_{parallelogram}=6\times5 \\ \\ A_{parallelogram}=30\text{ }units² \end{gathered}[/tex]

From the solution developed above, we are able to conclude that the correct answer for the present question is:

A. 30 units²
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