Question

An unknown gas is found to consist of 10.48 g of nitrogen and 11.96 g if oxygen. What is the percentage composition of this gas? * A. 53.3% N, 46.7% O B. 74.5% N, 25.5% O C. 28.6% N, 71.4 % O D. 46.7%N, 53.3%O

Answer 1

Answer:

A. 53.3% N, 46.7% O

Explanation:

1st) It is necessary to add both quantities (10.48g of nitrogen and 11.96g of oxygen) to obtain the total mass of the sample, which represents 100%:

10.48g + 11.96g = 22.44g

22.44g represents the 100% of the sample.

2nd) Now we can calculate the percentage composition of the gas, using a mathematical rule of three and the amount of nitrogen and oxygen:

• Nitrogen:

$\begin{gathered} 22.44g-100\% \\ 10.48g-x=\frac{10.48g*100\%}{22.44g} \\ x=46.7\% \end{gathered}$

• Oxygen:

$\begin{gathered} 22.44g-100\% \\ 11.96g-x=\frac{11.96g*100\%}{22.44g} \\ x=53.3\% \end{gathered}$

We can also calculate the oxygen percentage by subtracting 100% minus the nitrogen percentage (46.7%):

100% - 4607% = 53.3%

So, the percentage composition is 53.3% N and 46.7% O.