Question

(Score for Question 3: of 6 points)3. Felipe is ordering new carpet for his bedroom floor. (The floor is represented in the picture below asrectangle JKLM). He knows the base edge, ML, measures 18 ft. And the distance of diagonal KMmeasures 25 ft. What is the area of Felipe's bedroom floor? Show all work and round your answer tothe nearest tenth.JKM

Answer 1

Solution:

Given:

$\begin{gathered} The\text{ length of the room floor is 18 ft} \\ The\text{ width of the room floor is }x \end{gathered}$

Considering the right triangle KLM,

To get the width (x), we use the Pythagoras theorem.

$\begin{gathered} 18^2+x^2=25^2 \\ x^2=25^2-18^2 \\ x^2=625-324 \\ x^2=301 \\ x=\sqrt{301} \\ x=17.35ft \\ \\ Hence,\text{ the width is 17.35ft} \end{gathered}$

The area of the bedroom floor is;

$\begin{gathered} A=l\times w \\ A=18\times17.35 \\ A=312.3ft^2 \end{gathered}$

Therefore, the area of Felipe's bedroom floor to the nearest tenth is 312.3 square feet.