Question

what is the equation in point slope form of the line that passes through the point (5, 0) and has a slope of 1.2?

Answer 1

To see the equation we know that the general equation of a line is:

$y=mx+b$

Where m is the slope. So you know that the slope is 1.2, then you have an equation like this:

$y=1.2x+b$

Since b is just a number we can say that this is also equal to:

$y=1.2(x+c)$

We'll write it this way so it's similar to the options.

Then you know that the line pases through point (5,0). To find the value of constant c we replace the value of x and y from this point (x = 5 and y=0):

$0=1.2(5+c)$

And clear c from this expression

$0=5+c\Rightarrow c=-5$

So the answer is:

$y-0=1.2(x-5)$