Question

What must the final volume be for the pressure of the gas to be 1.56 atm at a temperature of 336 K?Express your answer in milliliters to three significant figures.

Answer 1

According to the Combined gas Law :

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

The problem gives P1 = 1.32 atm, V1 = 212 ml, T1 = 292 K, P2 = 1.56 atm, T2 = 336 K.Then you just have to subtitute and solve:

$V_2=\frac{P_1V_1}{T_1}\frac{T_2}{P_2}=\frac{1.32\text{ atm x 212 ml}}{292\text{ K}}\frac{336\text{ K}}{1.56\text{ atm}}=206\text{ ml}$