Question

In parallelogram DEFG, DE=6 Inches and DF= 6.4 Inches. Diagonals GE and DF Intersect at point H. If GH=4 inches, what is the length of GE?

Answer 1

SOLUTION

Consider the figure below:

It is given that the diagonals DF and GE intersects at H

Recall that the daigonals of parallelogram bisect each other

It follows:

$GH=HE$

Since it is given that GH=4, it follows:

$HE=4$

Using segment addition postulate, it follows:

$\begin{gathered} GE=GH+HE \\ GE=4+4 \\ GE=8 \end{gathered}$

Therefore the required answer is GE=8 inches