Respuesta :

[tex]15-8x>3-2x[/tex]

Add 8x to both sides

[tex]\begin{gathered} 15-8x+8x>3-2x+8x \\ 15>3+6x \end{gathered}[/tex]

Subtract 3 from both sides

[tex]\begin{gathered} 15-3>3-3+6x \\ 12>6x \end{gathered}[/tex]

Divide both sides by 6

[tex]\begin{gathered} \frac{12}{6}>\frac{6x}{6} \\ 2>x \\ x<2 \end{gathered}[/tex]

Interval notation solution: x < 2