Question

true or false18. In the circle: x^2+(y-2)^2=12, the radius is 12

Answer 1

The general equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center and r is the radius of the circle.

Comparing the given equation of a circle and the above general equation we get:

$r^2=12$

Then, the radius of this circle is:

$r=\sqrt[]{12}$

In conclusion, the sentence is false.