Question

(300/m) + 44n m=15 n=4

Answer 1

Solve (300/m) + 44n where m = 15 and n = 4

$\begin{gathered} (\frac{300}{m})+44n \\ \text{Substitute for the values of m and n, and you have;} \\ (\frac{300}{15})+44(4) \\ 20+176 \\ 196 \end{gathered}$

The solution to the expression is 196