Question

Diamond form and grouping to factored form a(x-r1)(x-r2) for the first problem on the picture

Answer 1

Given the expression:

$6x^2-13x-5$

We will factor the expression as follows:

The factors of 6 = 2 x 3 or 1 x 6

The factors of 5 = 1 x 5

The difference must be = -13

So, we will use the factors of 6 = 2 x 3

So, the factoring will be as follows:

$6x^2-13x-5=(3x+1)(2x-5)$

We will write the expression in the form a(x-r1)(x-r2) as follows:

$\frac{1}{6}(x+\frac{1}{3})(x-\frac{5}{2})$