Question

Use add or sub formula to write as trig fun tho on

Answer 1

$\frac{tan(43)-tan(18)}{1+tan(43)tan(18)}$

The formula to write this function is going to be:

$tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)*tan(b)}$

Substituing:

$\frac{tan(43)-tan(18)}{1+tan(43)tan(18)}=tan(43-18)$

In this case a= 43 and b=18:

$tan(43-18)=tan(25)=0.466\approx0.5$

The answer is: tan(25).