Question

a map has a scale on it which 3in represents 50 miles use information to match each map distance on the left to the number of miles to distant represent on the right

Answer 1

It is given that the scale used in the map is,

$3\text{ in}\equiv50\text{ miles}$

For 9 inches,

$9\text{ inches=3}\times(\text{3 inches)}\equiv\text{3}\times(\text{50 miles)}=150\text{ miles}$

Thus, a distance of 9 inches on the map corresponds to 150 miles in actual.

For 15 inches,

$15\text{ inches=5}\times(\text{3 inches)}\equiv5\times(\text{50 miles)}=250\text{ miles}$

Thus, a distance of 15 inches on the map corresponds to 250 miles in actual.

For 21 inches,

$21\text{ inches=7}\times(\text{3 inches)}\equiv7\times(\text{50 miles)}=350\text{ miles}$

Thus, a distance of 21 inches on the map corresponds to 350 miles in actual.