Solution:
Given:
[tex]16,16,9,9,9,7,16,10[/tex]The median is the middle term from the data rearranged in rank order.
Rearranging the data;
[tex]7,9,9,9,10,16,16,16[/tex]From the data set, the middle term is 9 and 10.
Since two terms fall in the middle, then the median is the mean of the two terms.
Hence,
[tex]\begin{gathered} Median=\frac{9+10}{2} \\ Median=\frac{19}{2} \\ Median=9.5hours \end{gathered}[/tex]Therefore, to the nearest tenth, the median is 9.5 hours.
The mean is the average of the set of data.
[tex]\begin{gathered} mean=\frac{16+16+9+9+9+7+16+10\:}{8} \\ mean=\frac{92}{8} \\ mean=11.5hours \end{gathered}[/tex]Therefore, to the nearest tenth, the mean is 11.5 hours