Question

4x 3y2 Evaluate the expression for x = 3 and y = 4.

Answer 1

$-\frac{9}{4}$

Explanation

$-\frac{4x^3}{3y^2}$

Step 1

to find the answer just replace the values for x and y

for x=3 and y =4

$\begin{gathered} -\frac{4x^3}{3y^2} \\ -\frac{4(3)^3}{3(4)^2}=-\frac{4\cdot(3\cdot3\cdot3)}{3\cdot(4\cdot4)}=-\frac{4\cdot27}{3\cdot16}=-\frac{27}{12}=-\frac{9}{4} \end{gathered}$

I hope this helps you