Question

write (2 to the power of -1) to the power of 3 with the same base but one exponent

Answer 1

$\frac{1}{8}$

Explanation

Step 1

$(2^{-1})^3$

remember

$\begin{gathered} a^{-n}=\frac{1}{a^n} \\ (a^n)^m=a^{n\cdot m} \\ (\frac{a}{b})^m=\frac{a^m}{b^m} \end{gathered}$

Step 2

solve

$\begin{gathered} (2^{-1})^3 \\ (2^{-1})^3=(\frac{1}{2^1})^3=(\frac{1^3}{2^3})=\frac{1}{8} \end{gathered}$