Question

Express sin 285 as a function of the reference angle.Question 19 options:sin75sin105-sin75sin-75

Answer 1

Given:

$\sin 285^{\circ}$

To express it as a function of reference angle:

Since the angle lies in the fourth quadrant.

So, the reference angle will be,

$\begin{gathered} \theta_{ref}=360-\theta_4 \\ \theta_{ref}=360^{\circ}-285 \\ \theta_{ref}=75^{\circ} \end{gathered}$

Therefore, the function of the reference angle is,

$\sin 75^{\circ}$