Question

6ft 3ft 8ft 16ft area of irregular figures

Answer 1

Solution.

From the figure given we will have to find the

(Area of A) + (The Area of B)

STEP 1 :

For figure B

b = 3

h = 6

$\begin{gathered} \text{Area of A = }\frac{1}{2}\times b\times h \\ \text{ = }\frac{1}{2}\times3\times6 \\ \text{ = }\frac{18}{2}\text{ = 9} \end{gathered}$

Step 2:

For Figure A

L = 16

b = 8ft

Area of B = L x B

= 16 x 8

= 128

STEP 3

Area of A + Area of B

128 + 9 = 137 square feet