Question

solve: 10+7-4y=-5+6y+22 and decide whether it has infinite solutions or no solutions or one solution

Answer 1

$\begin{gathered} 10+7-4y=-5+6y+22 \\ 17-4y=17+6y \\ 17-17-4y=17+6y-17 \\ -4y=6y \\ -4y-6y=6y-6y \\ -10y=0 \\ \frac{-10y}{-10}=\frac{0}{-10} \\ y=0 \end{gathered}$

answer is one solution