Respuesta :

Given data:

Comcentration of H+ ion in water,

[tex]\lbrack H^+\rbrack=10^{-7}\text{ }\frac{mol}{l}[/tex]

The pH value is given as,

[tex]pH=-\log _{10}\lbrack H^+\rbrack_{}[/tex]

Substituting all known values,

[tex]pH=-\log _{10}\lbrack10^{-7}\rbrack[/tex]

Since,

[tex]\log _{10}(a^b)=b\times\log _{10}(a)[/tex]

Therefore,

[tex]\begin{gathered} pH=-7\times(-\log _{10}\lbrack10\rbrack) \\ =7\log _{10}\lbrack10\rbrack \end{gathered}[/tex]

Since,

[tex]\log _{10}\lbrack10\rbrack=1[/tex]

Therefore,

[tex]\begin{gathered} pH=7\times1 \\ =7 \end{gathered}[/tex]

Therefore, pH of a pure water solution is 7.