Question

Given the function k(n) = -3n + 2, and its domain is described by the set {6,-8, 4, 2}, what is therange?

Answer 1

The domain of a function is the set of values where the function is defined (values of x where y is defined).

The range of a function are the values of the function where is defined (values of y).

For the given function:

$k(n)=-3n+2$

Domain: values of n {6,-8, 4, 2}

Range: values of k(n)

n= 6

$\begin{gathered} k(6)=-3(6)+2 \\ =-18+2 \\ =-16 \end{gathered}$

n=-8

$\begin{gathered} k(-8)=-3(-8)+2 \\ =24+2 \\ =26 \end{gathered}$

n=4

$\begin{gathered} k(4)=-3(4)+2 \\ =-12+2 \\ =-10 \end{gathered}$

n=2

$\begin{gathered} k(2)=-3(2)+2 \\ =-6+2 \\ =-4 \end{gathered}$

Then, the range is: {-16, 26, -10, -4}