Question

an octagon has side lengths 10.9 in the perimeter of the Octagon is 87.2 in centimeter and the area is 573.67 inches squared a second octagon has corresponding side lengths equal to 18.03 in find the area of the second octagon round to the nearest tenth

Answer 1

The are of the octsagon is given by:

$A=2a^2(1+\sqrt[]{2})$

where a is the lenght of its side.

Since the second octagon has sile lengths equal to 18.03, its area is:

$A=2(18.03)^2(1+\sqrt[]{2})=1563.6$

Therefore the area is 1563.6 squared centimeters