Hey there Ms or Mr could you please help me out with this problem?just so you know, this is Pythagorean theorem & Simplifying Radicals My recent tutor said that this is the answer of course no I don't have any doubts I just want to know if this is correct.

Hey there Ms or Mr could you please help me out with this problemjust so you know this is Pythagorean theorem amp Simplifying Radicals My recent tutor said that class=

Respuesta :

When we have a radical, we can simplify it by the rule:

[tex]\sqrt[]{ab}=\sqrt[]{a}\sqrt[]{b}[/tex]

So, we have to break down 500 into simpler radicals until we have a radical that can't be broken down. Let's simplify Root(500).

[tex]\sqrt[]{500}=\sqrt[]{50}\sqrt[]{10}[/tex]

Now, we can break down Root(50) further.

[tex]\begin{gathered} \sqrt[]{50}\sqrt[]{10} \\ =\sqrt[]{25}\sqrt[]{2}\sqrt[]{10} \end{gathered}[/tex]

Now, let's break down Root(10) also, thus we have:

[tex]\begin{gathered} \sqrt[]{25}\sqrt[]{2}\sqrt[]{10} \\ =\sqrt[]{25}\sqrt[]{2}\sqrt[]{5}\sqrt[]{2} \end{gathered}[/tex]

We can see:

• Root(25) is 5

,

• Also Root(2)*Root(2) is 2 by using the rule:

[tex]\sqrt[]{a}\sqrt[]{a}=a[/tex]

Thus, we finally have:

[tex]\begin{gathered} \sqrt[]{25}\sqrt[]{2}\sqrt[]{5}\sqrt[]{2} \\ =5(2)\sqrt[]{5} \\ =10\sqrt[]{5} \end{gathered}[/tex]