11, 8, 5, 2, -1
Option D is correct
Explanation:The given arithmetic sequence is:
[tex]a_n=14-3n[/tex]For the first term, substitute n = 1 into the arithmetic sequence
[tex]\begin{gathered} a_1=14-3(1) \\ a_1=14-3 \\ a_1=11 \end{gathered}[/tex]For the second term, substitute n = 2 into the arithmetic sequence
[tex]\begin{gathered} a_2=14-3(2) \\ a_2=14-6 \\ a_2=8 \end{gathered}[/tex]For the third term, substitute n = 3 into the arithmetic sequence
[tex]\begin{gathered} a_3=14-3(3) \\ a_3=14-9 \\ a_3=5 \end{gathered}[/tex]For the fourth term, substitute n = 4 into the arithmetic sequence
[tex]\begin{gathered} a_4=14-3(4) \\ a_4=14-12 \\ a_4=2 \end{gathered}[/tex]For the fifth term, substitute n = 5 into the arithmetic sequence
[tex]\begin{gathered} a_5=14-3(5) \\ a_5=14-15 \\ a_5=-1 \end{gathered}[/tex]Therefore, the first five terms are:
11, 8, 5, 2, -1