SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given inequality
[tex]\frac{7x+6}{2}\le3x+2[/tex]
STEP 2: Solve for x
[tex]\begin{gathered} \frac{7x+6}{2}\le3x+2 \\ \mathrm{Multiply\: both\: sides\: by\: }2 \\ 7x+6\le2(3x+2) \\ 7x+6\le\: 6x+4 \\ \mathrm{Subtract\: }6\mathrm{\: from\: both\: sides} \\ 7x+6-6\le\: 6x+4-6 \\ \text{By simplification,} \\ 7x\le\: 6x-2 \\ \mathrm{Subtract\: }6x\mathrm{\: from\: both\: sides} \\ 7x-6x\le\: 6x-2-6x \\ x\le\: -2 \end{gathered}[/tex]
STEP 3: Select the values that are a solution to the inequality
[tex]\begin{gathered} \text{ Since }x\le-2,\text{ this means that x is less than or equal to -2} \\ \text{This implies that all values less than or equal to 2 are a solution to the inequality} \\ \text{Looking at the options, the values that are less than or equal to 2 are:} \\ x=-3,x=-2 \end{gathered}[/tex]
Hence, the values that are a solution to the inequality are:
