A 6 kg sign is suspended by two strings making angles with the ceiling as shown in the diagram. Determine the magnitudes of the tensions in each string. Remember that 1kg exerts a force of 9.8 N. please use sine/cosine law for this question

A 6 kg sign is suspended by two strings making angles with the ceiling as shown in the diagram Determine the magnitudes of the tensions in each string Remember class=

Respuesta :

The triangle representing the given scenario is shown below

T1 and dT2 represents the tension in each spring

We would apply the sine rule which is expressed as

a/SinA = b/SinB = c/SinC

where

A, B and C are the angles of the triangle

a, b and c are the sides opposite the respective angles

Thus,

A = 42

a = T1

B = 23

b = T2

C = 115

c = 58.8

T1/sin42 = 58.8/sin115

By cross multiplying, it becomes

T1sin115 = 58.8sin42

T1 = 58.8sin42/sin115

T1 = 43.41

T2/sin23 = 58.8/sin115

By cross multiplying, it becomes

T2sin115 = 58.8sin23

T2 = 58.8sin23/sin 115

T2 = 25.35

The magnitude of the tension in each string are 43.41 N and 25.35 N

Ver imagen EmilyroseP264712