Question

The sum of two numbers is30. The sum of4 times the larger and6 times the smaller is128. Find the numbers.

Answer 1

let

the smaller number = x

the larger number = y

x + y = 30

4y + 6x = 128

$\begin{gathered} x+y=30 \\ 4y+6x=128 \\ x=30-y \\ 4y+6(30-y)=128 \\ 4y+180-6y=128 \\ -2y=128-180 \\ -2y=-52 \\ y=\frac{52}{2} \\ y=26 \\ x+y=30 \\ x+26=30 \\ x=30-26 \\ x=4 \end{gathered}$

The numbers are 4 and 26.