Respuesta :

Answer:

[tex]\lbrack H_3O^+\rbrack\text{ = }5.0\text{ }\times10^{-6\text{ }}moles\text{ per liter}[/tex]

Explanation:

By definition, the pH of a solution is the negative logarithm to base 10 of the concentration of Hydroxonium or oxonium ion

Mathematically, we have this as:

[tex]pH=-log\lbrack H_3O^+\rbrack_{}[/tex]

We can change the formula subject so we would have hydroxonium ion on the left

Mathematically, we have this as:

[tex]\lbrack H_3O^+\rbrack\text{ = ANTILOG (-pH)}[/tex]

Finally, we have the calculation as follows:

[tex]\lbrack H_3O^+\rbrack\text{ = antilog(-5.3) = }0.000005011872[/tex]

In the scientific form,we have this as:

[tex]5.0\text{ }\times10^{-6\text{ }}moles\text{ per liter}[/tex]