Answer:
The number of units that must be produced and sold to maximize the profit is 30 units
[tex]30\text{ units}[/tex]The maximum profit is;
[tex]\text{ \$900}[/tex]Explanation:
Given that the profit P(x) obtained by manufacturing and selling x units of a certain product is given by;
[tex]P(x)=60x-x^2[/tex]The maximum point is at;
[tex]P^{\prime}(x)=0[/tex]Differentiating P(x);
[tex]\begin{gathered} P^{\prime}(x)=60-2x=0 \\ 60-2x=0 \\ 2x=60 \\ x=\frac{60}{2} \\ x=30 \end{gathered}[/tex]The number of units that must be produced and sold to maximize the profit is 30 units
Substituting x into p(x);
[tex]\begin{gathered} P(30)=60(30)-30^2 \\ P(30)=900 \end{gathered}[/tex]The maximum profit is;
[tex]\text{ \$900}[/tex]