Question

An ox exerts a forwards force of 7100 N. If the ox has a weight of 8000 N, what is the minimum coefficient of static friction? (HINT: if there was no static friction the ox would slip and not move forward, what friction is required to allow the ox to move without slipping)

Answer 1

Given data

*An ox exerts a forwards force is F = 7100 N

*An ox has weight is N = 8000 N

The formula for the minimum coefficient of static friction is given as

$\begin{gathered} F=\mu_sN \\ \mu_s=\frac{F}{N} \end{gathered}$

Substitute the known values in the above expression as

$\begin{gathered} \mu_s=\frac{7100}{8000} \\ =0.887 \end{gathered}$

Hence, the minimum coefficient of static friction is 0.887