Question

Calculate the pH and pOH of aqueous solutions with the following concentrations.[OH﹘] = 1.0 x 10-7M

Answer 1

Answer;

pH = 7

pOH = 7

Explanations:

The formula for calculating the pOH of a solution is given as:

$pOH=-log[OH^-]$

Given the following parameter

$[OH^-]=1.0\times10^{-7}M$

Substitute

$\begin{gathered} pOH=-log(1.0\times10^{-7}) \\ pOH=-log(10^{-7}) \\ pOH=-(-7) \\ pOH=7 \end{gathered}$

Determine the pH of the solution

Recall that pH + pOH = 14, hence;

$\begin{gathered} pH=14-pOH \\ pH=14-7 \\ pH=7 \end{gathered}$

Hence the required pH and pOH of aqueous solution are 7 and 7 respectively