Question

what is the center and radius for the circle with equation (x-2)^2 + (y-5)^2=49

Answer 1

Solution

For this case we have the following equation given by:

$(x-2)^2+(y-5)^2=49$

The general equation of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

And for this case by direct comparison we have:

$r^2=49$

Then we have:

$r=\sqrt[]{49}=7$

And the center si given by C=(h,k)

From the equation given we have:

$C=(2,5)$