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Area of a triangle

The area of a triangle of base length b and height h is:

[tex]A=\frac{b\cdot h}{2}[/tex]

We are given the area as A=22 square inches and the base length b=4 inches. We are required to find the height.

Solving for h:

[tex]h=\frac{2\cdot A}{b}[/tex]

Substituting:

[tex]h=\frac{2\cdot22in^2}{4in}=\frac{44in^2}{4in}=11in[/tex]

The height is 11 inches

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