Question

(a). Please check and calculate the average value of time in each trial.(b). It says Make a distance vs. time line graph below using the average times in Data Table 1. You will need to make sureto include a title and labeled X and Y-axis with units.(c). Make a velocity vs. time line graph below using the average velocities in Data Table 2. You will need to makesure to include a title and labeled X and Y-axis with units.

Answer 1

(a). For the 10 yd distance, the value of time in each trial is,

1.89 s, 1.83 s, and 1.72 s

The average value of time for 10 yd distance is,

$\begin{gathered} t_1=\frac{1.89+1.83+1.72}{3} \\ t_1=1.81\text{ s} \end{gathered}$

Thus, the average time for 10 yd is 1.81 seconds.

For 20 yd distance, the value of time in each trial is,

3.12 s, 3.28 s, and 3.47 s

The average value of time for 20 yd is,

$\begin{gathered} t_2=\frac{3.12+3.28+3.47}{3} \\ t_2=3.29\text{ s} \end{gathered}$

Thus, the average time for 20 yd is 3.29 seconds.

For 30 yd distance, the value of time in each trial is,

5.55 s, 5.14 s, and 4.44 s

The average value of time for 30 yd is,

$\begin{gathered} t_3=\frac{5.55+5.14+4.44}{3} \\ t_3=5.04_{}\text{ s} \end{gathered}$

Thus, the average time for 30 yd is 5.04 seconds.

For 40 yd distance, the value of time for each trial is,

7.16 s, 7.24 s, and 6.78 s

The average value of time for 40 yd is,

$\begin{gathered} t_4=\frac{7.16+7.24+6.78}{3} \\ t_4=7.06\text{ s} \end{gathered}$

Thus, the average value of time for 40 yd is 7.06 seconds.