Question

Consider 4 consecutive odd integers. What is the sum of the 2nd and the 4th numbers if the first number is n?1. 2n+82.4n+123. n+64. 3n+6

Answer 1

4 consecutive odd integers

the next consecutive odd number is only 2 more than the first number so: n+2

n = first number

n + 2 = second number

n + 4 = third number

n + 6 = fourth number

the sum of the 2nd and the 4th numbers is:

n + 2 + n + 6 = n + n + 2 + 6 = 2n +8

2n + 8

Hence, option 1 is the correct answer