Given:
The stat of the team is given in the table.
Required:
We have to find in how many of 80 games will the team be tied at the end of neither half.
Explanation:
The total number of games given in the table is
[tex]4+8+12+3+6+9+5+4+9=60[/tex]The number of games in which the team has tied at the end of neither half is
[tex]4+8+3+6=21[/tex]Then the percentage of the team has tied at the end of neither half is
[tex]\frac{21}{60}\times100=0.35\times100=35\text{ \%}[/tex]Hence the number of games in which the team be tied at the end of neither half in those 80 games is
[tex]35\text{\% of }80=\frac{35}{100}\times80=0.35\times80=28[/tex]Final answer:
Hence the final answer is
[tex]28[/tex]