From the question, we are provided with the following information:
[tex]\begin{gathered} \text{Principal, P=\$19,400} \\ \text{Rate, r=5.07\%} \\ r=\frac{5.07}{100}=0.0507 \\ \text{Time, t(in years)=}\frac{32}{12}=2.67years \\ N\text{umber of times interest applied per time period, n=2(semi-annually)} \end{gathered}[/tex]The required parameter we are to find is the Amount, A.
Amount of a compound interest is given by the formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Thus, we have:
[tex]\begin{gathered} A=19,400(1+\frac{0.0507}{2})^{2\times2.67} \\ A=19400(1+0.02535)^{5.34} \\ A=19400(1.02535)^{5.34} \\ A=19400\times1.143 \\ A=\text{ \$22,174.76} \end{gathered}[/tex]Hence, the account will be worth $22,174.76 in 32 months