Question

‼️‼️IF ANSWERED W WORK SHOWN I WILL GIVE BRAINLIEST‼️‼️The electric field intensity between two large, parallel metal plates is 6000 N/C. The plates are 0.05 mapart. What is the electric potential difference between them?

Answer 1

We have the next information

E= 6000 N/C

d=0.05m

In order to find the electric potential difference we have the next formula

$\Delta V=Ed$

then we substitute the data given in the formula

$\Delta V=(6000\frac{N}{C})(0.05m)=300\frac{J}{C}=300V$

The electric potential difference between them is 300 V