The inequality is given as,
[tex]\frac{x-3}{x+6}\leq0[/tex]Note that the denominator can never be zero otherwise the rational function would become indeterminate. So we have to exclude the value at which the denominator,
[tex]\begin{gathered} x+6=0 \\ x=-6 \end{gathered}[/tex]So the function is not defined at x = - 6.
Consider that the division of the numbers can be non-positive, only if exactly one of the numbers is non-positive.
So we have to obtain the interval in which one of the factors is positive and the other is negative.
CASE-1: When the numerator is positive and the denominator is negative,