Question

what is the value of the expression when m=2 and n=-3. (4m^-3n^2)^2

Answer 1

Giving the funtion

$(4m^{-3}n^2)^2$

m=2

n=-3

$(4(2)^{-3}(-3)^2)^2$$(\frac{4}{2^3}(9))^2$$(\frac{36}{2^3})^2$$(\frac{36^2}{2^6})$$(\frac{2^49^2}{2^2*2^4})=\frac{9^2}{2^2}$$\frac{81}{4}$

then the evaluated function in m=2 n=-3

has a value of 81/4