Given
perimeter = 42 inches
length of a rectangle is 5 inches more than the width.
Find
width, length
Explanation
Let width of rectangle = x inches
length = 5 + x
Perimeter of rectangle = 2 (l + b) = 2(5+x+x) = 42
[tex]\begin{gathered} 2\times(5+x+x)=42 \\ 5+2x=21 \\ 2x=16 \\ x=8 \end{gathered}[/tex]width = 8 inches
Length = 5 + 8 = 13 inches
Final Answer
The width of the rectangle is 8 inches.
The length of the rectangle is 13 inches.
