Answer
P(Z and T)= 8/121
Explanation
The total out come in group 1 = 11
The number of z = 4
Probability of picking a Z in group 1 = 4 / 11
Group 2
The total out comes = 11
Number of T outcomes = 2
Probability of picking a T = 2/11
Therefore, P( Z and T) = P(Z) x P(T)
P(Z and T) = P(Z) x P(T)
P(Z) = 4/11
P(T) = 2/11
P(Z and T) = 4/11 x 2/11
P(z and T) = 8/121
Therefore, the probability of picking a Z and aT is 8/121