Question

confused on perimeter

Answer 1

The area will be, the area of the small square plus the area of the parallelogram plus the area of the rectangle.

The area of the square:

$As=l\cdot l=2\cdot2=4in^2$

The area of the parallelogram:

$Ap=B\cdot H=5\cdot3=15in^2$

The area of the rectangle:

$Ar=l\cdot w=5\cdot2=10in^2$

Therefore:

$\begin{gathered} A=As+Ap+Ar \\ A=4in^2+15in^2+10in^2 \\ A=29in^2 \end{gathered}$