Question

Write the slope-intercept form of the equation of the line describedthrough: (-5, 4), perp. to y=3/4x+4

Answer 1

Answer:

To find the equation of the line passes through (-5,4) and perpendicular to the line y=3/4 x +4

The slope of the line y=3x/4 +4 is 3/4

Let m be the slope of the required equation of the line,

Since these two lines are perpendicular to each other.

we know that,

Product of the slopes of the perpendicular lines is -1

That is,

$\frac{3}{4}\times m=-1$

$m=-\frac{4}{3}$

Slope of the required line is -4/3

Passes through the point (-5,4)

The equation of the line passes through the point (x1,y1) and m as its slope is

$(y-y1)=m(x-x1)$

Substitute x1=-5, y1=4 and m=-4/3

we get,

$(y-4)=-\frac{4}{3}(x+5)$

$y-4=-\frac{4}{3}x-\frac{20}{3}$

$y=-\frac{4}{3}x-\frac{20}{3}+4$

$y=-\frac{4}{3}x+\frac{(-20)+12}{3}$

$y=-\frac{4}{3}x-\frac{8}{3}$

The required slope-intercept form of the equation of the line is y=-4/3 x-8/3.