Question

Find the area of the triangle. Round to the nearest tenth. a=28.5 b=33.4 c=22.3

Answer 1

solution

for this case we can use the Herons formula given by:

$A=\sqrt[]{s(s-a)(s-b)(s-c)}$

Where s is the semiperimeter given by:

$s=\frac{a+b+c}{2}=\frac{33.4+28.5+22.3}{2}=42.1$

And we can find the area on this way:

$A=\sqrt[]{42.1(42.1-33.4)(42.1-28.5)(42.1-22.3)}=314.05$

And rounded to the nearest tenth would be:

314.1