From the given table
Choose two-point for x and y from the table
So,
The point will be:
(0, 3) and (1, 1)
Now,
From the standard for of the linear function
[tex]y=mx+b[/tex]Then,
First, find the value of the slope (m) from the given point
So,
From the formula of the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Then,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1_{}-3_{}}{1_{}-0_{}} \\ m=-2 \end{gathered}[/tex]Now,
To find the value of b, put the value of m = -2, x = 0 and y = 3 into the standard form of the equation
[tex]\begin{gathered} y=mx+b \\ 3=-2(0)+b \\ 3=b \end{gathered}[/tex]Then,
Put the value of b into the standard form of the equation
[tex]\begin{gathered} y=mx+b \\ y=-2x+3 \end{gathered}[/tex]Hence, the correct option is B.