The cost per ton of x = 300 is 318.18
To solve this, we need to reaplce x in the function:
[tex]\begin{gathered} \begin{cases}f(x)=\frac{262,500}{x+525} \\ x=300\end{cases} \\ f(300)=\frac{262,500}{300+525}=\frac{262,500}{825} \\ f(300)\approx318.18 \end{gathered}[/tex]And then we get the anser